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Correct Answer – A
When `HgI_(2)` is added to the aqueous solution of KI following reaction takes place.
`2KI+HgI_(2)rarrK_(2)[HgI_(4)]hArr2K^(+)+[HgI_(4)]^(2-)`
Thus there is a net decrease in number of ions present in solution. Two formula units of KI i.e., four ions decrease to three ions in `K_(2)[HgI_(4)]`.
As number of ions decreases `DeltaT_(f)` decrease of f.p. is raised.
Correct Answer – A
`2 KI + HgI_(2) rarr K_(2) HgI_(4)`. As a result of this reaction, no. of ions decrease. So the lowering in F pt. is less or the actual F. pt is more.