what will be the solution of equation sin θ = 0 ?
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Given
sin θ = 0
∵ sin θ = sin 0 = sin π = sin 2π = sin (–2π) = …. = 0
Therefore sin θ = 0 is satisfied by the following values of θ.
∴ θ = 0, ± π, ± 2π, ± 3π, ± 4π, …..
⇒ The general solution of sin θ = 0 is θ = nπ, n∈I