What is the equation of the straight line parallel to 2x – 3y = 1 and passes through the point (-3,2)
1. 2x – 3y – 1 = 0
2. 2x – 3y + 12 = 0
3. 3x – 2y = 1
4. 2x – 3y + 6 = 0
1. 2x – 3y – 1 = 0
2. 2x – 3y + 12 = 0
3. 3x – 2y = 1
4. 2x – 3y + 6 = 0
Correct Answer – Option 2 : 2x – 3y + 12 = 0
Concept:
Equation of a Line Parallel to a Line:
Let, ax + by + c = 0 (b ≠ 0) be the equation of the given straight line. So, the equation of a line parallel to a given line is ax + by + k = 0
Where k is constant.
The slopes of parallel lines are equal.
Calculation:
Hare, equation of the straight line parallel to 2x – 3y = 1
Let, equation of required line be 2x – 3y + k = 0
Now, this line passing through (-3, 2)
∴2(-3) – 3(2) + k = 0
⇒ -6 – 6 + k = 0
⇒ k = 12
∴ Equation of required line 2x – 3y + 12 = 0
Hence, option (2) is correct.