No. of bonds between two atoms.

(no. of bond pair electron – no. of lone pair electron) / 2
Bond order=no.of bond present around central atom÷no.of sigma bond

$$\\frac{y7656}{6657}$s
[tex] Mercury \\: Venus \\: Earth \\: Mars [/tex][tex] $$Mercury \\: Venus \\: Earth \\: Mars $$
The iron oxide has 69.9% iron and\xa030.1% dioxygen by mass.Thus, 100 g of iron oxide contains 69.9 g iron and 30.1 g dioxygen.The number of moles of iron present in 100 g of iron oxide are\xa0$$55.8/69.9\u200b=1.25$$.The number of moles of dioxygen present in 100 g of iron oxide are\xa0$$32/30.1\u200b=0.94$$.The ratio of the number of oxygen atoms to the number of carbon atoms present in one formula unit of iron oxide is\xa0$$1.252×0.94\u200b=1.5:1=3:2$$.Hence, the formula of the iron oxide is\xa0$$Fe2O3$$
Called*
The number of bonds between two atoms in a molecule is call bond order.