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Aishwarya Das
Asked: 2022-11-10T06:05:42+05:30 In:

Two wires are fixed in a sanometer. Their tension are in the ratio `8:1` The lengths are in the ratio `36:35` The diameter are in the ratio `4:1` Densities of the materials are in the ratio `1:2` if the lower frequency in the setting is `360Hz`. The beat frequency when the two wires are sounded together is
A. `5`
B. `8`
C. `6`
D. `10`

Two wires are fixed in a sanometer. Their tension are in the ratio `8:1` The lengths are in the ratio `36:35` The diameter are in the ratio `4:1` Densities of the materials are in the ratio `1:2` if the lower frequency in the setting is `360Hz`. The beat frequency when the two wires are sounded together is
A. `5`
B. `8`
C. `6`
D. `10`
Parabola
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  1. Correct Answer – D
    `(T_(1))/(T_(2)) =(8)/(1), (l_(1))/(l_(2)) = (36)/(35), (r_(1))/(r_(2)) = (4)/(1), (rho_(1))/(rho_(2)) = (1)/(2)`
    `(f_(1))/(f_(2)) = (l_(1))/(l_(2)) sqrt(T_(1)/(T_(2))(rho_(2))/(rho_(1)).(r_(2)^(2))/(r_(1)^(2)))`
    `= (35)/(36)sqrt((8)/(1).(2)/(1).((1)/(4))^(2)) = (35)/(36)`
    `f_(1) gt f_(2), f_(2) = 360`
    `f_(1) = (360 xx 36)/(35) = 370`
    Beat frequency `= f_(1)-f_(2) =10 Hz`

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Nakul Rao Mitter
Asked: 2022-11-08T11:53:28+05:30 In:

Two wires are fixed in a sanometer. Their tension are in the ratio `8:1` The lengths are in the ratio `36:35` The diameter are in the ratio `4:1` Densities of the materials are in the ratio `1:2` if the lower frequency in the setting is `360Hz`. The beat frequency when the two wires are sounded together is
A. `5`
B. `8`
C. `6`
D. `10`

Two wires are fixed in a sanometer. Their tension are in the ratio `8:1` The lengths are in the ratio `36:35` The diameter are in the ratio `4:1` Densities of the materials are in the ratio `1:2` if the lower frequency in the setting is `360Hz`. The beat frequency when the two wires are sounded together is
A. `5`
B. `8`
C. `6`
D. `10`
Parabola
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Leave an answer

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1 Answer

  1. Correct Answer – D
    Frequency in a stretched string is given by
    `n=(1)/(2l)sqrt((T)/(pir^2rho))=(1)/(l)sqrt((T)/(pir^2rho))`
    (d= Diameter of string).
    `implies=(n_1)/(n_2)=(l_2)/(l_1)sqrt((T_1)/(T_2)xx((d_2)/(d_1))^2xx((rho_2)/(rho_1)))`
    `=(35)/(36)sqrt((8)/(1)xx((1)/(4))^2xx(2)/(1))=(35)/(36)`
    `impliesn_2=(36)/(35)xx360=370`
    Hence beat frequency `=n_2-n_1=10`

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