Two identical containers connected by a fine caillary tube contain air at `N.T.P` if one of those containers is immersed in pure water, boiling under noramal pressure then new pressure is
A. `76 cm` of `Hg`
B. `152 cm` of `Hg`
C. `57 cm` of `Hg`
D. `87.76 cm` of `Hg`
A. `76 cm` of `Hg`
B. `152 cm` of `Hg`
C. `57 cm` of `Hg`
D. `87.76 cm` of `Hg`
Correct Answer – D
`(P_(1)V_(1))/(T_(1)) = `(P_(1)V_(1))/(T_(1)) = P_(1)((V_(1))/(T_(1)) + (V_(1))/(T_(1)))`