Correct Answer – Option 2 : 1/4

Given:

Two dice are thrown simultaneously

Concept used:

A dice has numbers from 1 to 6 i.e. {1, 2, 3, 4, 5, 6}.

Formula used:

Probability = (Total number of favourable outcome)/(Total number of outcome)

Calculation:

When two dice are thrown.

Then, The number of total possible outcome = 6 × 6 = 36

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2),…………………………., (2, 6)

……………………………………………………

……………………………………………………

(6, 1), (6, 2), …………………………..(6, 6)

To get the two numbers whose product is odd, both should be odd numbers.

So favourable outcome are:

(1,1), (1,3), (1,5), (3,1), (3,3), (3,5), (5,1), (5,3), (5,5)

Total number of favourable outcome = 9

Probability = (Total number of favourable outcome)/(Total number of outcome)

⇒ Probability = 9/36 = 1/4

∴ The probability of getting two numbers whose product is odd is 1/4.

Correct Answer – Option 1 : 1/6

Given:

Two dice are thrown simultaneously

Calculation:

When two dice are thrown simultaneously,

Number of possible outcomes are 36.

If getting the same number on both dice is taken as event,

Then for the 1^st event, 

⇒ Number of outcomes are 6.

For 2^nd event,

⇒ Number of outcomes/total number of possible outcomes

⇒ 6/(6 × 6)

⇒ 1/6

∴ The probability of getting the same number of both the dice is 1/6.