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Two dice are thrown simultaneously, the probability of obtaining a total score of 5 is
(1) 1/12
(2) 1/6
(3) 1/18
(4) 1/9
Two dice are thrown simultaneously, the probability of obtaining a total score of 5 is
(1) 1/12
(2) 1/6
(3) 1/18
(4) 1/9
Two dice are thrown simultaneously. The probability of obtaining a total score of 5 is
A. \(\frac{1}{18}\)
B. \(\frac{1}{12}\)
C. \(\frac{1}{9}\)
D. none of these
Two dice are thrown simultaneously. The probability of obtaining a total score of 5 is
A. \(\frac{1}{18}\)
B. \(\frac{1}{12}\)
C. \(\frac{1}{9}\)
D. none of these
As 2 dice are thrown so there are 6×6 = 36 possibilities.
Let E denote the event of getting a total score of 5.
E = {(1,4),(2,3),(3,2),(4,1)}
∴ n(E)=4
Hence,
P(E) = \(\frac{4}{36} = \frac{1}{9}\)
As our answer matches only with option (c)
∴ Option (c) is the only correct choice.
Two dice are thrown simultaneously. The probability of obtaining total score of seven is
A. \(\frac{5}{36}\)
B. \(\frac{6}{36}\)
C. \(\frac{7}{36}\)
D. \(\frac{8}{36}\)
Two dice are thrown simultaneously. The probability of obtaining total score of seven is
A. \(\frac{5}{36}\)
B. \(\frac{6}{36}\)
C. \(\frac{7}{36}\)
D. \(\frac{8}{36}\)
As 2 dice are thrown so there are 6×6 = 36 possibilities.
Let E denote the event of getting a total score of 5.
E = {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)}
∴ n(E)= 6
Hence,
P(E) = \(\frac{6}{36}\)
As our answer matches only with option (b)
∴ Option (b) is the only correct choice.
Correct option (4) 1/9
Explanation:
n(S) = 36
Favourable outcomes : (1, 4), (4, 1), (3, 2), (2, 3)
Required probability 4/36 = 1/9.