Two dice are thrown. If it is known that the sum of numbers on the dice was less than 6, the probability of getting a sum 3, is
A. 1/18
B. 5/18
C. 1/5
D. 2/5
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Let A be the event that the sum of numbers on the dice was less than 6
And, B be the event that the sum of numbers on the dice is 3
A={(1,4)(4,1)(2,3)(3,2)(2,2)(1,3)(3,1)(1,2)(2,1)(1,1)
N(A)=10
B={(1,2)(2,1)
n(B)=2
Required probability = nB/nA
Required probability = 2/10
Hence, The probability is 1/5