The volumes of two bodies are measured to be `V_1 = (10.2+-0.02) cm^3 and V_2 = (6.4 +- 0.01)cm^3`. Calculate sum and difference in volumes with error limits.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
given, `V_(1)=(10.2pm0.02)cm^(3)` and `V_(2)=(6.4pm0.01)m^(3)`
`DeltaV=pm(DeltaV_(1)+DeltaV_(2))`
`=pm(0.02+0.01)cm^(3)=pm0.03 cm^(3)`
`V_(1)+V_(2)=(10.2+6.4)cm^(3)=16.6 cm^(3)`
and `V_(1)+V_(2)=(10.2-6.4)cm^(3)=3.8 cm^(3)`
Hence, sum of volumes= `(16.6pm0.03)cm^(3)`
and difference of volumes= `(3.8pm0.03)cm^(3)`