The tamer of wild animals has to bring one by one 5 lions & 4 tigers to the circus arena. The number of ways this can be done if no two tigers immediately follow each other
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There are `6` spaces between `5` lions where `4` tiger can be arranged.
So, there are `C(6,4)` ways of tigers arranging between lions so that two tigers do not follow each other immediately.
Now, `4` tigers can be arranged in `4!` ways and `5` lions can be arranged in `5!` ways.
`:.` Required number of ways ` = C(6,4)*4!*5! = 15**24**120 = 43200`