The standard enthalpy of decomposition of the yellow complex `H_(3)NSO_(2)` into `NH_(3)` and `SO_(2)` is `+40 kJ mol^(-1)`. Calculate the standard enthalpy of formation of `H_(3)NSO_(3).DeltaH_(f)^(0)(NH_(3))= -46.17 kJ mol^(-1), DeltaH_(f)^(0)(SO)_(2)= -296.83`
Correct Answer – `-383 kJ mol^(-1)`