The reading of Centigrade thermometer coincides with that of Fahrenheit thermometer in a liquid. The temperature of the liquid is
A. `-40^(@)C`
B. `0^(@)C`
C. `100^(@)C`
D. `300^(@)C`
A. `-40^(@)C`
B. `0^(@)C`
C. `100^(@)C`
D. `300^(@)C`
Correct Answer – A
`((F – 32)/(180) = (C – 0)/(100))`