The pressure and temperature of `4 dm^(3)` of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be
A. `2 dm^(3)`
B. `3 dm^(3)`
C. `4 dm^(3)`
D. `8 dm^(3)`
A. `2 dm^(3)`
B. `3 dm^(3)`
C. `4 dm^(3)`
D. `8 dm^(3)`
Correct Answer – C
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2)), (P_(1)xx4)/(T_(1))= (2P_(1)xxV_(2))/(2T_(1))`
`8=2xxV_(2)` so `V_(2)= 4dm^(2)`