The number of ways in which 26 identical chocolates be distributed between Amy, Bob, Cathy and Daniel so that each receives at least one chocolate and Amy receives more chocolates than Bob is _______.
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Total number of natural solution of equation x1 + x2 + x3 + x4 = 26 is 25C3 = 2300. total number of natural solution of equation 2x1 + x3 + x4 = 26 = 1 + 3 + + 23 = 144
Total number of natural solution of equation x1 + x2 + x3 + x4 = 26 when x1 > x2 is 2300 – 144/2 = 1078