The number of selection of n objects from 2n objects of which n are identical and the rest are different is
(A) 2n
(B) 2n – 1
(C) 2n – 1
(D) 2n –1 + 1
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The correct option (A) 2n
Explanation:
nC0 + nC1 + nC2 …… + nCn
= 2n