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Nilam Harjo
Asked: 2022-11-09T14:14:16+05:30 In:

The length of the compound microscope is `14 cm.` The magnifying power for relaxed eye is `25`. If the focal length of eye lens is `5 cm`, then the object distance for objective lens will be
A. `1.8 cm`
B. `1.5 cm`
C. `2.1 cm`
D. `2.4 cm`

The length of the compound microscope is `14 cm.` The magnifying power for relaxed eye is `25`. If the focal length of eye lens is `5 cm`, then the object distance for objective lens will be
A. `1.8 cm`
B. `1.5 cm`
C. `2.1 cm`
D. `2.4 cm`
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  1. Correct Answer – a

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Satish Bhat
Asked: 2022-11-06T22:14:42+05:30 In:

The length of the compound microscope is `14 cm.` The magnifying power for relaxed eye is `25`. If the focal length of eye lens is `5 cm`, then the object distance for objective lens will be
A. 1.8 cm
B. 1.5 cm
C. 2.1 cm
D. 2.4 cm

The length of the compound microscope is `14 cm.` The magnifying power for relaxed eye is `25`. If the focal length of eye lens is `5 cm`, then the object distance for objective lens will be
A. 1.8 cm
B. 1.5 cm
C. 2.1 cm
D. 2.4 cm
Parabola
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1 Answer

  1. Correct Answer – A
    Length of compound microscope,
    `L_(oo)=v_(o)+f_(e )rArr 14 v_(o)+5`
    `therefore ” ” v_(o)=9 cm`
    Mgnifying power of microscope for relaxed eye
    `M=(v_(o))/(u_(o)).(D)/(f_(e ))` or `25=(9)/(u_(o)).(25)/(5)`
    or distant of object, `u_(o)=(9)/(5)=1.8 cm`

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