The geometry of a complex species can be understood from the knowledge of type of hybridisation of orbitals of central atom. The hybridisation of orbitals of central atom in `[B(OH_(4))]^(-)` and the geometry of the complex are respectively.
A. `sp^(3)`, tetrahedral
B. `sp^(3)`, square planar
C. `sp^(3)d^(2)`, octahedral
D. `dsp^(2)`, square planar
A. `sp^(3)`, tetrahedral
B. `sp^(3)`, square planar
C. `sp^(3)d^(2)`, octahedral
D. `dsp^(2)`, square planar
Correct Answer – A
Structure of `B(OH)_(4)^(-)` is
`{:(” “OH),(” |”),(HO-B^(-)-OH),(” |”),(” “OH),(“4 bond pair + 0 lone pair”):}`
Hybridisation – `sp^(3)`
Geometry – Tetrahedral.