The general solution of the equation, `2cot.(theta)/(2)=(1+cot theta)^(2)` is `(n in Z)`
A. `n pi+(-1)^(n)(pi)/(4)`
B. `n pi+(-1)^(n)(pi)/(6)`
C. `n pi+(-1)^(n)(pi)/(3)`
D. none of these
A. `n pi+(-1)^(n)(pi)/(4)`
B. `n pi+(-1)^(n)(pi)/(6)`
C. `n pi+(-1)^(n)(pi)/(3)`
D. none of these
Correct Answer – B
`2cot.(theta)/(2)=(1+cot thetas)^(2)`
`rArr (2.2 cos theta//2.cos theta//2)/(2 sin theta//2.cos theta//2)=(1+cos theta)^(2)`
`rArr (2(1+cos theta))/(sin theta)=cosec^(2)theta + 2 cos theta`
`rArr sin theta =1//2`
`rArr theta = n pi +(-1)^(n)(pi)/(6), n in Z`