The flow rate of water from a tap of diameter 1.25 cm is `0.48 L//mi n`. The coefficient of viscosity of water is `10^(-3) Pa-s`. After sometime, the flow rate is increased to `3L//mi n`. Characterise the flow for both the flow rates.
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`N_(R)=(rho upsilon D)/(eta) = (rho D)/(eta) ((V)/(pi D^(2)//4))`
`=(4 rho V)/(pi eta D)`…(i)
In first case,
`rho = 10^(3) kg//m^(3) , D = 1.25 xx 10^(-2) m`
`V= (0.48 xx 10^(-3))/(60)m^(3) s^(-1) , eta = 10^(-3)Pa-s`
Putting the value in teh relation (i) , we shall get, `N_(R) = 5095`, which is more than 3000. Thus, the flow of liquid is turbulent.