The floor of a hall consists of 290 tiles which are rhombus-shaped and the length of the diagonals is 39 m and 30 m. What is the total cost of painting the floor at the rate of Rs. 3 per m2?
1. Rs. 508950
2. Rs. 508995
3. Rs. 508935
4. Rs. 608945
The floor of a hall consists of 290 tiles which are rhombus-shaped and the length of the diagonals is 39 m and 30 m. What is the total cost of painting the floor at the rate of Rs. 3 per m2?
1. Rs. 508950
2. Rs. 508995
3. Rs. 508935
4. Rs. 608945
1. Rs. 508950
2. Rs. 508995
3. Rs. 508935
4. Rs. 608945
Correct Answer – Option 1 : Rs. 508950
Given:
Diagonals of the small tiles are 39 m and 30 m
Total number of tiles = 290
Rate of painting = Rs. 3 per m2
Formula used:
Area of Rhombus = (d1 × d2)/2
Here, d1 and d2 are diagonals of a rhombus
Concept used:
All sides of a rhombus are equal and diagonals bisect each other at a right angle.
Calculation:
Area of Rhombus = (d1 × d2)/2
⇒ Area = (39 × 30)/2
⇒ Area = 585 m2
Total area of hall’s floor = 585 × 290 = 169650 m2
Cost of painting floor = 169650 × 3 = Rs. 508950
∴ The cost of painting the floor of the hall is Rs. 508950