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Moti Dev Master
Asked: 2022-10-29T05:32:14+05:30 In:

The ends of the base of an isosceles triangle are at `(2a, 0)and (0, a).` The equation of one side is `x = 2a. `The equation of the other side, is
A. x + 2y – a = 0
B. x + 2y = 2a
C. 3x + 4y – 4a = 0
D. 3x – 4y + 4a = 0

The ends of the base of an isosceles triangle are at `(2a, 0)and (0, a).` The equation of one side is `x = 2a. `The equation of the other side, is
A. x + 2y – a = 0
B. x + 2y = 2a
C. 3x + 4y – 4a = 0
D. 3x – 4y + 4a = 0
Parabola
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  1. Correct Answer – D

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