The coordinate of a moving point at time t are given by x = a ( 2t + sin 2t) , y = a ( 1-cos 2t). Prove that acceleration is constant.
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x=a(2t+sin2t)
`dx/dt=2a+a-cos2t*2`
`d^x/dt=0+2a-sin2x2i`
`=-4asin2thati`
`dy/dt=asin2t*2`
`d^y/dt^2=2a*2cos2t`
`=4acos2thatj`
`|veca|=sqrt(a_x^2+a_y^2)`
`=sqrt(16a^2sin^2t+16a^2cos^2 2t)`
`=sqrt(16a^2)`
=4a.