The block is allwed to fall, slowly from the position wher spring is in its natural length. Find, maximum extension in the string.
Since the block falls slowly from rest maximum extension occurs when
`mg = Kx_(0)`
`x_(0) = (mg)/(K)` is maximum extension, Ans.` (mg)/(K)`
Since the block falls slowly from rest maximum extension occurs when
`mg = Kx_(0)`
`x_(0) = (mg)/(K)` is maximum extension, Ans.` (mg)/(K)`