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Nagma Prabhat Gour
Asked: 2022-11-06T22:17:19+05:30 In:

Ten tuning forks are arranged in increasing order of frequency is such a way that any two nearest tuning forks produce `4 beast//sec`. The highest freqeuncy is twice of the lowest. Possible highest and the lowest frequencies are
A. 80 and 40
B. 100 and 50
C. 44 and 22
D. 72 and 36

Ten tuning forks are arranged in increasing order of frequency is such a way that any two nearest tuning forks produce `4 beast//sec`. The highest freqeuncy is twice of the lowest. Possible highest and the lowest frequencies are
A. 80 and 40
B. 100 and 50
C. 44 and 22
D. 72 and 36
Parabola
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  1. Correct Answer – D

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Jagat Jaggi
Asked: 2022-11-03T00:57:32+05:30 In:

Ten tuning forks are arranged in increasing order of frequency is such a way that any two nearest tuning forks produce `4 beast//sec`. The highest freqeuncy is twice of the lowest. Possible highest and the lowest frequencies are
A. 72, 144
B. 36, 72
C. 18, 36
D. 9, 18

Ten tuning forks are arranged in increasing order of frequency is such a way that any two nearest tuning forks produce `4 beast//sec`. The highest freqeuncy is twice of the lowest. Possible highest and the lowest frequencies are
A. 72, 144
B. 36, 72
C. 18, 36
D. 9, 18
Parabola
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  1. Correct Answer – B
    `N = (n_(L) – n_(F))/(x) +1`
    `10 = (2n_(F) – n_(F))/(4) + 1`
    `9 xx 4 = n_(F)`
    `n_(F) = 36`

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Aditya Faisal Bath
Asked: 2022-10-29T04:29:57+05:30 In:

Ten tuning forks are arranged in increasing order of frequency is such a way that any two nearest tuning forks produce `4 beast//sec`. The highest freqeuncy is twice of the lowest. Possible highest and the lowest frequencies are
A. 80 and 40
B. 100 and 50
C. 44 and 32
D. 72 and 36

Ten tuning forks are arranged in increasing order of frequency is such a way that any two nearest tuning forks produce `4 beast//sec`. The highest freqeuncy is twice of the lowest. Possible highest and the lowest frequencies are
A. 80 and 40
B. 100 and 50
C. 44 and 32
D. 72 and 36
Parabola
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1 Answer

  1. Correct Answer – D
    In n is frequency of first fork, then frequency of the last (10th fork) `= n + 4(10 -1) = 2n`
    `:. N = 36 and 2n = 72`

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