Subtract the first rational number from the second in each of the following:
(i) \(\frac{3}{8}, \frac{5}{8}\)
(ii) \(\frac{-7}{9}, \frac{4}{9}\)
(iii) \(\frac{-2}{11}, \frac{-9}{11}\)
(iv) \(\frac{11}{13}, \frac{-4}{13}\)
(v) \(\frac{1}{4}, \frac{-3}{8}\)
(vi) \(\frac{-2}{3}, \frac{5}{6}\)
(vii) \(\frac{-6}{7}, \frac{-13}{14}\)
(viii) \(\frac{-8}{33}, \frac{-7}{22}\)
(i) \(\frac{5}{8}-\frac{3}{8}\) = \(\frac{5-3}{8}\)
= \(\frac{2}{8}\) (Therefore, L.C.M of 8 and 8 is 8)
= \(\frac{1}{4}\)
(ii) \(\frac{4}{9}-\frac{-7}{9}\) = \(\frac{4+7}{9}\)
= \(\frac{11}{9}\) (Therefore, L.C.M of 9 and 9 is 9)
(iii) \(\frac{-9}{11}-\frac{-2}{11}\) = \(\frac{-9+2}{11}\)
= \(\frac{-7}{11}\) (Therefore, L.C.M of 11 and 11 is 11)
(iv) \(\frac{-4}{13}-\frac{11}{13}\) = \(\frac{-4-11}{13}\)
= \(\frac{-15}{13}\) (Therefore, L.C.M of 13 and 13 is 13)
(v) \(\frac{-3}{8}-\frac{1}{4}\) = \(\frac{-3-2}{8}\)
= \(\frac{-5}{8}\) (Therefore, L.C.M of 8 and 4 is 8)
(vi) \(\frac{5}{6}-\frac{-2}{3}\) = \(\frac{5+4}{6}\)
= \(\frac{9}{6}\) (Therefore, L.C.M of 6 and 3 is 6)
(vii) \(\frac{-13}{14}-\frac{-6}{7}\) = \(\frac{-13+12}{14}\)
= \(\frac{-1}{14}\) (Therefore, L.C.M of 14 and 7 is 14)
(viii) \(\frac{-7}{22}-\frac{-8}{33}\) = \(\frac{-21+16}{66}\)
= \(\frac{-55}{66}\) (Therefore, L.C.M of 22 and 33 is 66)