Solve the quadratic equation:
ix2 – 4x – 4i = 0
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Solve the quadratic equation:
ix2 – 4x – 4i = 0
Solve the quadratic equation:
ix2 – 4x – 4i = 0
Given as ix2 – 4x – 4i = 0
ix2 + 4x(–1) – 4i = 0 [as we know, i2 = –1]
Therefore by substituting –1 = i2 in the above equation, we get
ix2 + 4xi2 – 4i = 0
i(x2 + 4ix – 4) = 0
x2 + 4ix – 4 = 0
x2 + 4ix + 4(–1) = 0
x2 + 4ix + 4i2 = 0 [Since, i2 = –1]
x2 + 2ix + 2ix + 4i2 = 0
x(x + 2i) + 2i(x + 2i) = 0
(x + 2i) (x + 2i) = 0
(x + 2i)2 = 0
x + 2i = 0
x = –2i, -2i
Therefore, the roots of the given equation are –2i, –2i