Solve the equation by transposing the terms and check your result : 14 = 27 – x
2a – 3 = 5
2a = 5 + 3 (transposing – 3)
2a = 8 (transposing x 2)
a = 4
Check
LHS = 2a – 3 = 2 x 4 – 3 = 8 – 3 = 5
RHS =5
∴ L.H.S = R.H.S
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Solve the equation by transposing the terms and check your result : 14 = 27 – x
Solve the equation by transposing the terms and check your result : 14 = 27 – x
Solve the equation by transposing the terms and check your result : 2a – 3 = 5
Solve the equation by transposing the terms and check your result : 2a – 3 = 5
2a – 3 = 5
2a = 5 + 3 (transposing – 3)
2a = 8 (transposing x 2)
a = 4
Check
LHS = 2a – 3 = 2 x 4 – 3 = 8 – 3 = 5
RHS =5
∴ L.H.S = R.H.S
Solve the equation by transposing the terms and check your result : 5(x + 4) = 35
Solve the equation by transposing the terms and check your result : 5(x + 4) = 35
5(x + 4) = 35
x + 4 = 35/5 (transposing x 5)
x + 4 = 7
x = 7 – 4 (transposing + 4)
x = 3
Check
LHS = 5(3 + 4) = 5 x 7 = 35
RHS = 35
∴ L.H.S = R.H.S
Solve the equation by transposing the terms and check your result : 3(x-3)=5(2x + 1)
Solve the equation by transposing the terms and check your result : 3(x-3)=5(2x + 1)
3(x – 3)=5(2x+ 1)
3(x – 3)= 5(2x ÷ 1)
3x – 9= 10x+5
3x = 10x + 5 ÷ 9 (transposing – 9)
3x = 10x + 14
3x – 10x = 14(transposing+ 10 x) – 7x =14
x = 14/-7 (transposing x ( – 7))
Check
LHS = 3(x – 3) = 3[( – 2) – 3] = 3x( – 5) = – 15
RHS = 5(2x + 1) = 5 x [2( – 2) + 1] = 5 x [ – 4 + 1]
= 5 x ( – 3)= – 15
∴ LH.S = R.H.S
14 = 27 – x
0 = 27 – x – 14 (transposing + 14)
0 = 13 – x (transposing – x)
x = 13
Check
LHS = 14
RHS = 27 – x = 27 – 13 = 14
∴ L.H.S = R.FIS