Solution of equation x2 + x – 2 = 0 in Roster form is:
(A) {1, 2}
(B) {-1, 2}
(C) {-1, -2}
(D) {1, -2}
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Answer is (D)
Given, x2 + x – 2 = 0
x2 + 2x – x – 2 = 0
x(x + 2) – 1(x + 2) = 0
(x + 2)(x – 1) = 0
when x + 2 = 0 then x = -2
when x – 1 = 0 then x = 1
Hence, roster form of equation is {-2, 1} or {1, -2}