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Chhavi Suraj Chad
Asked: 2022-11-10T15:33:37+05:30 In:

`sinxtanx-1=tanx-sinx`
A. `2npipm(3pi)/(4), npi+(-1)^(n)(pi)/(2), ninZ`
B. `npipm(3pi)/(4), npi+(-1)^(n)(pi)/(2), ninZ`
C. `2npi+(pi)/(4), npi+(-1)^(n)(pi)/(2), ninZ`
D. `npi+(pi)/(4), npi+(-1)^(n)(pi)/(2), ninZ`

`sinxtanx-1=tanx-sinx`
A. `2npipm(3pi)/(4), npi+(-1)^(n)(pi)/(2), ninZ`
B. `npipm(3pi)/(4), npi+(-1)^(n)(pi)/(2), ninZ`
C. `2npi+(pi)/(4), npi+(-1)^(n)(pi)/(2), ninZ`
D. `npi+(pi)/(4), npi+(-1)^(n)(pi)/(2), ninZ`
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1 Answer

  1. Correct Answer – B

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