Rearragne the following (I to IV) in the order of increasing masses and choose the correct answer (Atomic masses O=16, Cu=63 and N=4)
I. 1 Molecule of oxygen
II. 1 atom of nitrogen
IIIgt `1xx 10^(-10)`g atomic weight of copper
`
A. II lt I lt III lt IV
B. IV lt III lt II lt I
C. II lt III lt I lt IV
D. III lt IV lt I lt II
I. 1 Molecule of oxygen
II. 1 atom of nitrogen
IIIgt `1xx 10^(-10)`g atomic weight of copper
`
A. II lt I lt III lt IV
B. IV lt III lt II lt I
C. II lt III lt I lt IV
D. III lt IV lt I lt II
a) I. 1 molecule of `O_(2)` = (32)/(6.022 xx 10^(23)` = 5.3 xx 10^(-23)`g
(ii) 1. atom of N= (14)/(6.022 xx 10^(23)`g = `2.3 xx 10^(-23)`g
IIIgt `10^(-19)` g molecular weight of oxygen
`= (10^(-10) xx 32 = 3.2 xx 10^(-9)`g
IV. `10^(-10)`g atomic weight of copper `= 10^(-10) xx 63 =6.3 xx 10^(-9)`g
`therefore` Order of increasing mass is
II lt I lt III lt IV