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Fakaruddin Bhalla
Fakaruddin Bhalla
Asked: 3 years ago2022-11-08T15:33:52+05:30 2022-11-08T15:33:52+05:30In: General Awareness

Radioactive decay follows first order kinetics and the rate constant is often termed as decay constant. Certain radioactive substances may undero sequential decays in order to convert into a stable nucleus. The series comprising all such elements is termed as radioactive disintegration series.
A radioactive series is formed such that after each ` alpha` decay there are two consecutive `beta` decay and the cycle repeats. How many different elements this series can have if there are 12 members in the series ?
A. 12
B. 4
C. 3
D. 6

Radioactive decay follows first order kinetics and the rate constant is often termed as decay constant. Certain radioactive substances may undero sequential decays in order to convert into a stable nucleus. The series comprising all such elements is termed as radioactive disintegration series.
A radioactive series is formed such that after each ` alpha` decay there are two consecutive `beta` decay and the cycle repeats. How many different elements this series can have if there are 12 members in the series ?
A. 12
B. 4
C. 3
D. 6
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  1. 6702c
    2022-11-05T13:26:09+05:30Added an answer about 3 years ago

    Correct Answer – C
    After a very long time `: lambda_(1)N_(A)=lambda_(2)N_(B)`
    `(N_(A))/(N_(B))=(lambda_(1))/(lambda_(2))=(4 xx 10^(-2))/(16 xx10^(-5))=(1)/(4)=10^(-7)=2.5 xx 10^(-8) `

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Gauransh Oommen
Gauransh Oommen
Asked: 3 years ago2022-11-01T22:44:37+05:30 2022-11-01T22:44:37+05:30In: General Awareness

Radioactive decay follows first order kinetics and the rate constant is often termed as decay constant. Certain radioactive substances may undero sequential decays in order to convert into a stable nucleus. The series comprising all such elements is termed as radioactive disintegration series.
A substance A undergoes sequential decay as shown `A overset(lambda_(1))rarr B overset (lambda_(2))rarr C`. If the decay constant `lambda_(1)` and `lambda_(2)` are `4 xx10^(-2) “min”^(-1)` and `16 xx 10^(5) “min” ^(-1)` respectively then the molar ratio of B to A after a very long time will be :
A. `2.5 xx 10^(-8)`
B. `4 xx 10^(-2)`
C. `(1)/(16 )xx 10^(-5)`
D. `4 xx 10^(7)`

Radioactive decay follows first order kinetics and the rate constant is often termed as decay constant. Certain radioactive substances may undero sequential decays in order to convert into a stable nucleus. The series comprising all such elements is termed as radioactive disintegration series.
A substance A undergoes sequential decay as shown `A overset(lambda_(1))rarr B overset (lambda_(2))rarr C`. If the decay constant `lambda_(1)` and `lambda_(2)` are `4 xx10^(-2) “min”^(-1)` and `16 xx 10^(5) “min” ^(-1)` respectively then the molar ratio of B to A after a very long time will be :
A. `2.5 xx 10^(-8)`
B. `4 xx 10^(-2)`
C. `(1)/(16 )xx 10^(-5)`
D. `4 xx 10^(7)`
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  1. 1f531
    2022-10-30T08:34:04+05:30Added an answer about 3 years ago

    Correct Answer – A
    `[._(z)X^(A) underset (-alpha)rarr ._(z-2)X^(A-4)underset(-beta)rarr ._(z-1)X^(A-4)underset(-beta)rarr ._(z)X^(A-4)`
    `:.` In this series there will be three will be three different element with atomic no A, A-2, Z-1]

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