Pure Si at 300 K has equal electron (ni) and hole concentration (p) of 1.5 X 10^16 m^-3. Doping by indium increases p to 4.5 X 10^22 m^-3. What is n in the doped silicon?
(a) 4.5 X 10^9 m^-3
(b) 4.5 X 10^22 m^-3
(c) 5 X 10^9 m^-3
(d) 5 X 10^22 m^-3
(a) 4.5 X 10^9 m^-3
(b) 4.5 X 10^22 m^-3
(c) 5 X 10^9 m^-3
(d) 5 X 10^22 m^-3
The correct choice is (c) 5 X 10^9 m^-3
Best explanation: Here, ni = 1.5 X 10^16 m^-3, p = 4.5 X 10^22 m^-3
We know, np = ni^2
n = ni^2/p
= 5 X 10^9 m^-3.