Prove the following identities :
sin2θ – cos2 ϕ = sin2ϕ – cos2θ
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Prove the following identities :
sin2θ – cos2 ϕ = sin2ϕ – cos2θ
Prove the following identities :
sin2θ – cos2 ϕ = sin2ϕ – cos2θ
Taking LHS = sin2 θ – cos2 φ
=( 1 – cos2 θ) – (1 – sin2 φ) [∵ cos2 θ + sin2 θ = 1] & [∵ cos2 φ + sin2 φ = 1]
= 1 – cos2 θ – 1 + sin2 φ
= sin2 φ – cos2 θ
= RHS
Hence Proved