Prove that
(i) `[hat(i)hat(j)hat(k)]=[hat(j)hat(k)hat(i)]=[hat(k)hat(j)hat(i)]=1`
(ii)`[hat(i)hat(k)hat(j)]=[hat(k)hat(j)hat(i)]=[hat(j)hat(i)hat(k)]=1`
(i) `[hat(i)hat(j)hat(k)]=[hat(j)hat(k)hat(i)]=[hat(k)hat(j)hat(i)]=1`
(ii)`[hat(i)hat(k)hat(j)]=[hat(k)hat(j)hat(i)]=[hat(j)hat(i)hat(k)]=1`
Correct Answer – B
`[hat(i)hat(j)hat(k)]=(hat(i)xxhat(j)).hat(k)=hat(k).hat(k)=1`.