Prove that. cosA-sinA+1/cosA+sinA-1 =cosecA +cotA
Just open 1 in “cosA-sinA+1” then take common cosA+sinA
divide both numerator and denominator by sinQand then put the value of 1 from1+cosscQ =cotQ.
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Just open 1 in “cosA-sinA+1” then take common cosA+sinA
divide both numerator and denominator by sinQand then put the value of 1 from1+cosscQ =cotQ.
It\’s ncert example and already solved
LHS : = CotA-1+cosecA/CotA+1-CosecA. (Divide the both the value by “SinA”) = CotA+CosecA-(Cosec^2A-Cot^2A) / CotA-CosecA+1. (1=cosec^2A-cot^2A) = (CotA+CosecA)-(cosec^2A+cot^2A)/CotA-CosecA+1 = (CotA+CosecA)-(CosecA+CotA)(CosecA-CotA) = CotA+CosecA-(CotA-CosecA+1)/CotA-CosecA+1 = CotA+CosecA PROVED!!!!Its a question NCERT EX-8.4 Q5 (v) part…