Pentaborane B5H9(s) burns vigorously in O2 to give B2O3(s) and H2O(l). Calculate ΔH°rxn for the combustion of 1 mol of B5H9.
ΔH°f[B2O3(s)] = –1,273.5 kJ/mol
ΔH°f[B5H9(s)] = 73.2 kJ/mol
ΔH°f[H2O(l)] = –285.8 kJ/mol
(A) –1,2735 kJ/mol
(B) –4,543 kJ/mol
(C) –18,170 kJ/mol
(D) –9,086 kJ/mol
(E) –8,448 kJ/mol
(B) –4,543 kJ/mol