A. Number of moles of `CO_(2)` molecule `=(“Weight in gram of” CO_(2))/(“molecular weight of ” CO_(2))=(88)/(44)=2` mol
B. 1 mole of a substance `=N_(A)` molecules `=6.022xx10^(23)` molecuels
=Avogadro number
`=6.022xx10^(23)` molecuels of `H_(2)O=1` mol
C. 22.4L of `O_(2)` at StP=1 mol
D. Number of moles of 96g of `O_(2)=(96)/(32)”mol”=3″mol”`
E. 1 mole of any gas=Avogadro number `=6.022xx10^(23)` molecuels

Correct Answer – A::B::C::D

Correct Answer – A::B::C::D

Correct Answer – A(r); B(s) ;C(q); D(p)

Correct Answer – A(q), B(p,r,t ), C(q,s), D(p )

Correct Answer – A(s), B(r ), C(q), D(p)

(i) 0.95 is very likely to happen, so it is close to 1.
(ii) 0.02 very little chance of happening because probability is very low.
(iii) -0.3 an incorrect assignment because probability of any events lie between 0 and 1.
(iv) 0.5, as much chance of happening as not because sum of chances of happening and not happening is zero.
(v) 0, no chance of happening.

Correct Answer – A::B::C::D

Correct Answer – A::B::C::D

Correct Answer – A
(A) `underset(“10 g”)underset(“100 g”) (CaCO_(3))overset(Delta)to CaCO + underset(“0.224L”)underset(“22.4 L”)(CO_(2))`
(B) `underset(“1.06g”)underset(“1 mol (106g)”)(Na_(2)CO_(3))+ 2HCl to 2NaCl + H_(2)O+ underset(“0.224 L”)underset(“22.4L”)(CO_(2))`
(C) `underset(“12g”)underset(“2.4g”)(C) + O_(2) to underset(“0.448L”)underset(“22.4L”)(CO_(2))`
(D) `underset(“0.56 g”)underset(“28 g”)(CO) + (1)/(2)O_(2) to underset(“0.448L”)underset(“22.4 L”)(CO_(2))`

Correct Answer – 1-D, 2-A, 3-B, 4-C, 5-F, 6-E

Correct Answer – A::B::C::D

Correct Answer – (A)Q,T,U(B)Q,T,U(C)Q,T,U

Correct Answer – A::B::C::D

Correct Answer – A::B::C::D

Correct Answer – A::B::C::D

Correct Answer – A::B::C::D

A(q,s),B(ps),C(p,r),D(p,r,t)

Correct Answer – A::B::C::D

Correct Answer – (A-p,q,s,u); (B-s, t, u); (C-r,t); (D-s,t)
`Delta_(f)H^(@)` and `Delta_(f)G^(@)` are zero for species in their standard states
from III law entropy of a perfectly crystalline solid is zero at 0 K.

Correct Answer – A::B::C::D

Correct Answer – A(q), B(p ), C(s), D(r )

(c) a – iii, b – iv, c – i, d – ii.

Correct Answer – A::B::C::D
Follow definitions of molarity, molarity and more frations.

Correct Answer – A::B::C::D

Correct Answer – A::B::C::D

Correct Answer – B

Correct Answer – A::B::C::D

Correct Answer – A(q,s), B(q,s ), C(p,r), D(p,r )

1. – c 

2. – d 

3. – a 

4. – b

[A] (a-6), (b-8), (c-7), (d-1),(e-2),(f-3),(g-4),(h-5)
[B] (a-5), (b-7), (c-8), (d-2), (e-1), (f-3), (g-4), (h-6).

Correct Answer – A::B::C::D

`Ararr4Brarr4Crarr2,3Drarr1,3`
A. Photon has particle nature as well as wave nature it exhibits both momentum and wavelength
B. Electron also has particle nature as well as wave nature. Thus, it also exhibits both momentum and wavelength.
C. `psi^(2)` represents probability density of electron and always has positive values.
D. Principal quantum numb er `n=4` for N-shell. ltbr. K L M N
n=1 2 3 4
It always has positive values.

Correct Answer – A-rt ; B-pt ; C-s ; D-qt

Correct Answer – A::B::C::D

Correct Answer – A(r),B(p),C(s),D(q)