(k-1)x^2=kx-1 find K so that one root is -3
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
(k-1)x^2=kx-1This can be written as;(k-1)x^2-(kx-1)=0(k-1)x^2-kx+1=0Put x= -3 as this is a zero of polynomial: (k-1)(-3)^2-k(-3)+1=0 (k-1)(9)+3k+1=0 9k-9+3k+1=0 9k+3k-9+1=0 12k-8=0 12k=8 k=8/12 k=2/3So, the value of k is 2/3 so that one of the zero of this polynomial is -3.#Hope this may be helpful for you…