`intsqrt(1+x^(2))dx` बराबर है :
A. `(x)/(2)sqrt(1+x^(2))+(1)/(2)log|(x+sqrt(1+x^(2)))|+C`
B. `(2)/(3)(1+x^(2))^((3)/(2))+C`
C. `(2)/(3)x(1+x^(2))^((3)/(2))+C`
D. `(x^(2))/(2)sqrt(1+x^(2))+(1)/(2)x^(2)log|x+sqrt(1+x^(2))|+C`
A. `(x)/(2)sqrt(1+x^(2))+(1)/(2)log|(x+sqrt(1+x^(2)))|+C`
B. `(2)/(3)(1+x^(2))^((3)/(2))+C`
C. `(2)/(3)x(1+x^(2))^((3)/(2))+C`
D. `(x^(2))/(2)sqrt(1+x^(2))+(1)/(2)x^(2)log|x+sqrt(1+x^(2))|+C`
Correct Answer – a
माना `I=int sqrt(1+x^(2))dx`
`rArr” “I=(x)/(2)sqrt(1+x^(2))+(1)/(2)log||x+sqrt(1+x^(2))|+C`