In the given figure if AD ⊥ BC, prove that AB2 + CD2 = BD2 + AC2.
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In the given figure if AD ⊥ BC, prove that AB2 + CD2 = BD2 + AC2.
In the given figure if AD ⊥ BC, prove that AB2 + CD2 = BD2 + AC2.
Given: In △ABC, AD ⊥ BC.
R.T.P: AB2 + CD2 = BD2 + AC2
Proof: △ABD is a right angled triangle
AB2 – BD2 = AD2 ……. (1)
△ACD is a right angle triangle
AC2 – CD2 = AD2………… (2)
From (1) and (2)
AB2 – BD2 = AC2 – CD2
AB2 + CD2 = BD2 + AC2