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Wafiq Dev Edwin
Asked: 2022-11-11T22:21:33+05:30 In:

In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be
image
A. 10 mV
B. 0.1 V
C. 1.0 V
D. 10 V

In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be
image
A. 10 mV
B. 0.1 V
C. 1.0 V
D. 10 V
Parabola
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  1. Correct Answer – C

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Vikrant Amin
Asked: 2022-11-11T17:40:51+05:30 In:

In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be
image
A. 10 mV
B. 0.1 V
C. 1.0 V
D. 10 V

In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be
image
A. 10 mV
B. 0.1 V
C. 1.0 V
D. 10 V
Parabola
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1 Answer

  1. Correct Answer – C
    `(V_(0))/(V_(“in”))=beta(R_(i))/(R_(“in”))rArrV_(0)=beta(R_(i))/(R_(“in”))xxV_(“in”)=100xx(10kOmega)/(1kOmega)xx1mV=1V`

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Bijoy Nirmal Jani
Asked: 2022-11-07T23:08:08+05:30 In:

In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be
image
A. `10 mV`
B. `0.1V`
C. `1.0V`
D. `10V`

In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be
image
A. `10 mV`
B. `0.1V`
C. `1.0V`
D. `10V`
Parabola
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1 Answer

  1. Correct Answer – C
    `”Voltage gain” (“Output voltage”)/(“Input voltage”)`
    `implies V_(out)=V_(“in”)xx”Voltage gain”`
    `implies V_(out)=V_(“in”)xx”Current gain”xx”Resistance gain”`
    `=V_(“in”)xxbetaxx(R_(L))/(R_(BE))=10^(-3)xx100xx10/1=1V`.

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Gulab Albert Upadhyay
Asked: 2022-10-29T10:33:02+05:30 In:

In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be
image
A. `10mV`
B. `0.1V`
C. `1.0V`
D. `10V`

In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be
image
A. `10mV`
B. `0.1V`
C. `1.0V`
D. `10V`
Parabola
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1 Answer

  1. Correct Answer – C
    `DeltaI_(B)=(v_(i))/(R_(in))=(10^(-3))/(10^(3))=10^(-6)A`
    `DeltaI_(c )=betaDeltaI_(B)=100xx10^(-6)=10^(-4)A`
    `v_(0)=DeltaI-(c )R_(L)=10^(-4)xx10xx10^(3)=1V`

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