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Meghana Ramachandran
Asked: 2022-11-11T19:22:52+05:30 In:

In the arrangement shown in Fig. 7.100 , mass can be hung from a string with a linear mass density of `2 xx 10^(-3) kg//m` that passes over a light pulley . The string is connected to a vibrator of frequency `700 Hz` and the length of the string between the vibrator and the pulley is `1 m`.
image
If the standing waves are observed , the largest mass to be hung is
A. `16 kg`
B. `25 kg`
C. `32 kg`
D. `400 kg`

In the arrangement shown in Fig. 7.100 , mass can be hung from a string with a linear mass density of `2 xx 10^(-3) kg//m` that passes over a light pulley . The string is connected to a vibrator of frequency `700 Hz` and the length of the string between the vibrator and the pulley is `1 m`.
image
If the standing waves are observed , the largest mass to be hung is
A. `16 kg`
B. `25 kg`
C. `32 kg`
D. `400 kg`
Parabola
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  1. Correct Answer – D
    For largest mass , `p = 1`
    `n = (p)/( 2L) sqrt((T)/(mu))`
    `700 = (p)/( 2L) sqrt((T)/(mu))`
    ` m = 2 xx 10^(-3) kg//m , L = 1 m`
    `T = [ ( 700)^(2) xx 4 xx 1 xx 2 xx 10^(-3)] = 3920 N`
    Largest mass to be hang , `M_(max) = 3920//9.8 = 400 kg`

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Ram Gopal Sehgal
Asked: 2022-11-02T06:22:25+05:30 In:

In the arrangement shown in Fig. 7.100 , mass can be hung from a string with a linear mass density of `2 xx 10^(-3) kg//m` that passes over a light pulley . The string is connected to a vibrator of frequency `700 Hz` and the length of the string between the vibrator and the pulley is `1 m`.
image
If the mass suspended is `16 kg` , then the number of loops formed in the string is
A. `1`
B. `3`
C. `5`
D. `8`

In the arrangement shown in Fig. 7.100 , mass can be hung from a string with a linear mass density of `2 xx 10^(-3) kg//m` that passes over a light pulley . The string is connected to a vibrator of frequency `700 Hz` and the length of the string between the vibrator and the pulley is `1 m`.
image
If the mass suspended is `16 kg` , then the number of loops formed in the string is
A. `1`
B. `3`
C. `5`
D. `8`
Parabola
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  1. Correct Answer – C
    Number of loops formed
    `P = 2nL sqrt((mu)/(T)) = 2 xx 700 xx 1 sqrt((2 xx 10^(-3))/(16 xx 9.8))`
    ` = ( 2xx 700)/( 280) = 5`

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Mini Thaker
Asked: 2022-10-29T05:34:55+05:30 In:

In the arrangement shown in Fig. 7.100 , mass can be hung from a string with a linear mass density of `2 xx 10^(-3) kg//m` that passes over a light pulley . The string is connected to a vibrator of frequency `700 Hz` and the length of the string between the vibrator and the pulley is `1 m`.
image
The string is set into vibrations and represented by the equation ` y = 6 sin (( pi x)/( 10)) cm cos (14 xx 10^(3) pi t)` where `x` ane `y` are in `cm` , and `t` in `s`, the maximum displacement at `x = 5 m` from the vibrator is
A. `6 cm`
B. `3 cm`
C. `5 cm`
D. `2 cm`

In the arrangement shown in Fig. 7.100 , mass can be hung from a string with a linear mass density of `2 xx 10^(-3) kg//m` that passes over a light pulley . The string is connected to a vibrator of frequency `700 Hz` and the length of the string between the vibrator and the pulley is `1 m`.
image
The string is set into vibrations and represented by the equation ` y = 6 sin (( pi x)/( 10)) cm cos (14 xx 10^(3) pi t)` where `x` ane `y` are in `cm` , and `t` in `s`, the maximum displacement at `x = 5 m` from the vibrator is
A. `6 cm`
B. `3 cm`
C. `5 cm`
D. `2 cm`
Parabola
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  1. Correct Answer – A
    `A(x) = 6 sin ( pi x)/(10)`
    Maximum displacement at `x = 5 cm`
    `A(x) = 6 sin ((pi)/(10) xx 5 ) = 6 cm`

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