In nuclear fission, 0.01% mass is converted into energy. The energy released by the fission of 100 kg mass will be:
A. `9 xx 10^(15) j`
B. `9 xx 10^(11) kJ`
C. `9 xx 10^(17) j`
D. `9 xx 10^(13) J`
A. `9 xx 10^(15) j`
B. `9 xx 10^(11) kJ`
C. `9 xx 10^(17) j`
D. `9 xx 10^(13) J`
Correct Answer – b
`Delta m = 100 xx (0.01)/(100) = 0.01 kg`
`E = Delta mc^(2) = 0.01 xx (3 xx 10^(8))^(2) J`
`= 9 xx 10^(14) J = 9 xx 10^(11) kJ`