In a `p-n` junction the depletion region is `400 nm` wide and electric field of `5 xx 10^(5) Vm^(-1)` exists in it. The minimum energy of a conduction electron, which can diffuse from n-side to the p-side is.
A. `4 eV`
B. `5 eV`
C. `0.4 eV`
D. `0.2 eV`
A. `4 eV`
B. `5 eV`
C. `0.4 eV`
D. `0.2 eV`
Correct Answer – D
`W = Vq = Edq`
`= 5 xx 10^(5) xx 400 xx 10^(-9) xx 1.6 xx 10^(-19) J`
`= (5 xx 10^(5) xx 400 xx 10^(-9) xx 1.6 xx 10^(-19)J)/(1.6 xx 10^(-19))eV`
`= 2000 X 10^(-4) eV = 0.2 eV`.