In a double-slit experiment, the slits are separated by a distance d and the screen is at a distance D from the slits. If a maximum is formed just opposite to each slit, then what is the order or the fringe so formed?
A. `(d^(2))/(2 lambda D)`
B. `(2 d^(2))/( lambda D)`
C. `(d^(2))/( lambda D)`
D. `(d^(2))/(4 lambda D)`
A. `(d^(2))/(2 lambda D)`
B. `(2 d^(2))/( lambda D)`
C. `(d^(2))/( lambda D)`
D. `(d^(2))/(4 lambda D)`
Correct Answer – a
`y_(n) (max) = n(D lambda)/(d)`
Hence, `y_(n) (max) = d // 2`
So, `n (d lambda)/(d) = (d)/(2)` or `n = (d^(2))/(2 lambda D)`