Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Correct Answer – A
First we re-write the equations of the two lines in such a way that the values of the expressions on the left hand sides of the equality for x = 1 , y = 1 become positive .
Re-writing the given equations , we obtain
-x-y + 3 = 0 and – 2x + y + 2 = 0.
Now , we obtain the bisector of the angle containing point (1,1) for positive sign. The required bisector is given by
`(-x-y + 3)/(sqrt((-1)^(2) + (-1)^(2))) = + (-2 x + y + 2)/(sqrt(-2)^(2) + 1^(2))`
`implies (sqrt5 – 2 sqrt2 ) x + (sqrt5 + sqrt2)y – 3sqrt5 + 2sqrt2 = 0` .
Correct Answer – A