If x=-1/2,is a solution of the quadratic equation 3x^2 +2kx-3=0,find value of k.
Correct Answer – `k=(-9)/(4)`
Since `x=(-1)/(2)` is a solution of `3x^(2)+2kx-3=0,` we have
`3xx((-1)/(2))^(2)+2kxx((-1)/(2))-3=0`
`implies” “(3)/(4)-k-3=0impliesk=((3)/(4)-3)=(-9)/(4).`
So easy put the value of x in given eqn