If we decrease kinetic energy 19% then find percentage decrement in momentum..
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9.24%
K= p /2mp= square root.2mKDecrease in Kinetic energy= 19% of Ki.e 19/100 * K = 0.19 KFinal K.E , K\’= 0.81Final momentum, p\’ = square rt. 2mK\’ = sqr. rt. 2m x 0.81K= 0.9 square root 2mK = 0.9pincrease in pp-p\’/p x 100 = p-0.9p/p x 100 = 10%