If the non parallel sides of a trapezium are equal.prove it is cyclic
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If the non parallel sides of a trapezium are equal prove it is acyclix
If the non parallel sides of a trapezium are equal prove it is acyclix
Given – AB || CD , AD = BC T.P. – ABCD is a cyclic Construction – BE || AD Proof – Here AB||CD & AD = BC ABED is a parallelogram => BAD = BED – 1 eq.Also AD =BC = BE Therefore ,. BE = BC Angle BEC = angle BCE – 2 eq. Now, angle BED + angle BEC = 180 ( L.P. ) angle BAC + angle BCE = 180 ( from 1 & 2eq. ) angle A + angle C = 180 Therefore ,. ABCD is a cyclic.